**124: Binary Tree Maximum Path Sum** A path in a binary tree is a sequence of nodes where each pair of adjacent nodes in the sequence has an edge connecting them. A node can only appear in the sequence at most once. Note that the path does not need to pass through the root. The path sum of a path is the sum of the node's values in the path. Given the root of a binary tree, return the maximum path sum of any non-empty path.

class Solution:
    def maxPathSum(self, root: Optional[TreeNode]) -> int:
        self.max_sum = float('-inf')

        def dfs(node):
            if not node:
                return 0

            # Recursively get max gain from left and right
            left_gain = max(dfs(node.left), 0)  # only take positive gains
            right_gain = max(dfs(node.right), 0)

            # Path that passes through this node (might be best)
            current_max_path = node.val + left_gain + right_gain

            # Update the global max_sum if needed
            self.max_sum = max(self.max_sum, current_max_path)

            # Return max gain extendable to parent
            return node.val + max(left_gain, right_gain)

        dfs(root)
        return self.max_sum
Metric Value
Time O(n)
Space O(h) (stack)

Arrays and Strings

**3: Longest Substring Without Repeating Characters** ❗MEDIUM

Given a string s, find the length of the longest substring without duplicate characters.

Example 1:

Input: s = "abcabcbb"
Output: 3
Explanation: The answer is "abc", with the length of 3.

Example 2:

Input: s = "bbbbb"
Output: 1
Explanation: The answer is "b", with the length of 1.

Example 3:

Input: s = "pwwkew"
Output: 3
Explanation: The answer is "wke", with the length of 3.
Notice that the answer must be a substring, "pwke" is a subsequence and not a substring.
class Solution:
    def lengthOfLongestSubstring(self, s: str) -> int:
        char_set = set()
        left = 0
        max_length = 0

        for right in range(len(s)):
            while s[right] in char_set:
                char_set.remove(s[left])
                left += 1

            char_set.add(s[right])
            max_length = max(max_length, right - left + 1)

        return max_length
Metric Complexity
Time O(n)
Space O(min(n, m))

**8: String to Integer (atoi)** ❗ MEDIUM

Implement the myAtoi(string s) function, which converts a string to a 32-bit signed integer.

The algorithm for myAtoi(string s) is as follows:

  1. Whitespace: Ignore any leading whitespace (" ").
  2. Signedness: Determine the sign by checking if the next character is '-' or '+', assuming positivity if neither present.
  3. Conversion: Read the integer by skipping leading zeros until a non-digit character is encountered or the end of the string is reached. If no digits were read, then the result is 0.
  4. Rounding: If the integer is out of the 32-bit signed integer range [-231, 231 - 1], then round the integer to remain in the range. Specifically, integers less than 231 should be rounded to 231, and integers greater than 231 - 1 should be rounded to 231 - 1.

Return the integer as the final result.

Example 1:

Input: s = "42"

Output: 42

Explanation:

The underlined characters are what is read in and the caret is the current reader position.
Step 1: "42" (no characters read because there is no leading whitespace)
         ^
Step 2: "42" (no characters read because there is neither a '-' nor '+')
         ^
Step 3: "42" ("42" is read in)
           ^

Example 2:

Input: s = " -042"

Output: -42

Explanation:

Step 1: "-042" (leading whitespace is read and ignored)
            ^
Step 2: "-042" ('-' is read, so the result should be negative)
             ^
Step 3: "   -042" ("042" is read in, leading zeros ignored in the result)
               ^

Example 3:

Input: s = "1337c0d3"

Output: 1337

Explanation:

Step 1: "1337c0d3" (no characters read because there is no leading whitespace)
         ^
Step 2: "1337c0d3" (no characters read because there is neither a '-' nor '+')
         ^
Step 3: "1337c0d3" ("1337" is read in; reading stops because the next character is a non-digit)
             ^

Example 4:

Input: s = "0-1"

Output: 0

Explanation:

Step 1: "0-1" (no characters read because there is no leading whitespace)
         ^
Step 2: "0-1" (no characters read because there is neither a '-' nor '+')
         ^
Step 3: "0-1" ("0" is read in; reading stops because the next character is a non-digit)
          ^

Example 5:

Input: s = "words and 987"

Output: 0

Explanation:

Reading stops at the first non-digit character 'w'.

class Solution:
    def myAtoi(self, s: str) -> int:
        i = 0
        n = len(s)
        sign = 1
        result = 0
        
        # Step 1: Skip leading spaces
        while i < n and s[i] == ' ':
            i += 1
        
        # Step 2: Check for sign
        if i < n and (s[i] == '+' or s[i] == '-'):
            if s[i] == '-':
                sign = -1
            i += 1
        
        # Step 3: Read digits
        while i < n and s[i].isdigit():
            digit = int(s[i])
            result = result * 10 + digit
            i += 1
        
        # Step 4: Apply sign
        result *= sign
        
        # Step 5: Clamp to 32-bit signed integer range
        INT_MIN = -2**31
        INT_MAX = 2**31 - 1
        
        if result < INT_MIN:
            return INT_MIN
        if result > INT_MAX:
            return INT_MAX
        return result
Metric Complexity
Time O(n) (one pass through the string)
Space O(1) (constant extra space)